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Solve what is ask in each problem.
1. In a class, there are 20 boys and 25 girls, if one student is chosen at random. What is the probability of
a. Choosing a boy?
b. Choosing a girl?​

Sagot :

✒️MATH

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ANSWER:

[tex]\tt{Add \: the \: boys \: and \: girls}[/tex]

  • [tex]\tt 20 \: + \: 25 \: = \: 45[/tex]

[tex]\tt{so,}[/tex]

  • [tex]\tt \: \frac{20}{45} \: and \: \frac{25}{45}[/tex]

[tex]\tt{Their \: GCF \: is \: 5}[/tex]

  • [tex]\tt \: \frac{20 \: \div \: 5 \: = \: 4}{45 \: \div \: 5 \: = \: 9} \: \: \: \: \: \: \frac{25 \: \div \: 5 \: = \: 5}{45 \: \div \: 5 \: = \: 9}[/tex]

[tex]\tt{Convert \: fraction \: to \: decimal.}[/tex]

  • [tex]\tt\frac{4}{9} \: × \: 100 \: = \: 44.44[/tex]
  • [tex]\tt\frac{5}{9} \: × 100 \: = \: 55.56[/tex]

[tex]\tt{The \: answer \: is}[/tex]

  • [tex] \sf\green {a. \: \frac{4}{9} \: \: or \: 44.44\% \: is \: the \: probability \: of \: boys} \\ \\ \sf\green {b. \: \frac{5}{9} \: \: or \: 55.56\% \: is \: the \: probability \: of \: girls}[/tex]

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