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Find the number/s that if 12 is added to its square the result is 13 times the number I will give 10 pts

Sagot :

If n is the number, the equation is:

n² + 12 = 13n

Transform to ax² + bx + c = 0 (Quadratic Equation)

n² - 13n + 12 = 0

Solve by factoring:
(n - 12) (n - 1) = 0

Solve for the roots (n):
 n - 12 = 0               n - 1 =0
  n = 12                   n = 1

The number (n) is: { 12, 1}

To check if n = 12:

(12)² + 12 = 13 (12)

144 + 12 = 256
256 = 256