Suriin ang IDNStudy.com para sa malinaw at detalyadong mga sagot. Anuman ang kahirapan ng iyong mga tanong, ang aming komunidad ay may mga sagot na kailangan mo.
Sagot :
✒️VARIATIONS
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \large\underline{\mathbb{PROBLEM}:} [/tex]
- If r varies directly as s and inversely as the square of u, and r=2 when s=18 and u=2. find out r when u=3 and s=27
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \large\underline{\mathbb{ANSWER}:} [/tex]
[tex] \qquad \Large \:\: \rm{r = \frac{\,4\,}{3}} \\ [/tex]
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \large\underline{\mathbb{SOLUTION}:} [/tex]
» Create the equation of a combined variation in which k is the constant.
- [tex] r = \frac{\,ks\,}{u^2} \\ [/tex]
» Find the constant of the variation.
- [tex] 2 = \frac{\,k(18)\,}{2^2} \\ [/tex]
- [tex] 2 = \frac{\,k(18)\,}{4} \\ [/tex]
- [tex] 2 = \frac{\,k(9)\,}{2} \\ [/tex]
- [tex] 2\cdot\frac{\,2\,}{9} = \frac{\,k(9)\,}{2} \cdot \frac{\,2\,}{9} \\ [/tex]
- [tex] \frac{\,4\,}{9} = k \\ [/tex]
» The constant is 4/9. Find r when u is 3 and s is 27.
- [tex] r = \frac{\,\frac49s\,}{u^2} \\ [/tex]
- [tex] r = \frac{\,\frac49(27)\,}{3^2} \\ [/tex]
- [tex] r = \frac{\,\frac{108}9\,}{9} \\ [/tex]
- [tex] r = \frac{\,12\,}{9} \\ [/tex]
- [tex] r = \frac{\,4\,}{3} \\ [/tex]
[tex] \therefore [/tex] The value of r is 4/3
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
(ノ^_^)ノ
✒️[tex]\large{\mathcal{ANSWER}}[/tex]
[tex]======================[/tex]
If r varies directly as s and inversely as the square of u, and r=2 when s=18 and u=2. find out r when u=3 and s=27.
[tex] \: \boxed{r = \frac{4}{3}} [/tex]
[tex]------------------[/tex]
Computation / Solution;
[tex]set \: r = m \frac{s}{u {}^{2} } [/tex]
r = 2 when s = 18 , u = 12
[tex]2 = m = \frac{18}{ {2}^{2} } [/tex]
[tex]2 = m = \frac{18}{4} [/tex]
[tex]18m = 8[/tex]
[tex]m = \frac{4}{9} [/tex]
[tex]r = \frac{4s}{9 {u}^{2} } [/tex]
when u = 3, s = 27
[tex]r = \frac{4 \times 27}{9 \times {3}^{2} } [/tex]
[tex]r = \frac{4 \times 27}{9 \times 3 \times 3} [/tex]
[tex]r = \frac{4}{3} [/tex]
So the answer is [tex]r = \frac{4}{3} [/tex]
Pinahahalagahan namin ang bawat ambag mo. Huwag kalimutang bumalik at magtanong ng mga bagong bagay. Ang iyong kaalaman ay napakahalaga sa ating komunidad. Para sa mabilis at maasahang mga sagot, bisitahin ang IDNStudy.com. Nandito kami upang tumulong sa iyo.