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Answer:
first you need to figure out the energy of ONE photon with that wavelength. Using E= hc/lambda, you get E = 1.99 * 10^-20 J/photon. Now, how many photons do you need to add up to get to one kilojoule =1000 joules? 1000J / (1.99 * 10^-20 J/photon) =approximately 5 * 10^22 photons
Explanation: