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What is the answer of (3ײ-×)+(ײ+12×-5)+(2ײ+7)

Sagot :

Answer:

(3ײ-×)+(ײ+12×-5)+(2ײ+7)   =   [tex]6x^2+11x+2[/tex]

Step-by-step explanation:

simplify: (3ײ-×)+(ײ+12×-5)+(2ײ+7)

[tex]=3x^2-x+x^2+12x-5+2x^2+7[/tex]

[tex]Group\:like\:terms[/tex]:

[tex]=3x^2+x^2+2x^2-x+12x-5+7[/tex]

[tex]\mathrm{Add\:the\:numbers:}\:-5+7=2[/tex]

[tex]=3x^2+x^2+2x^2-x+12x+2[/tex]

[tex]\mathrm{Add\:similar\:elements:}\:3x^2+x^2+2x^2=6x^2[/tex]

[tex]=6x^2-x+12x+2[/tex]

[tex]\mathrm{Add\:similar\:elements:}\:-x+12x=11x[/tex]

[tex]=6x^2+11x+2[/tex]

so the answer is [tex]=6x^2+11x+2[/tex]