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A certain oxide of nitrogen forms from the combination of 7 grams of nitrogen and 4 grams of oxygen. What is the correct empirical formula of the compound? (atomic weights: N = 14? 0 = 16)
a. N2O
b. NO2
c. N2O4
d. N203

Sagot :

Letter A is the answer here is my solution
For N: 7g N x (1 mol N/14g N) = 0.5 mol N
For O: 4g O x (1 mol O/16g O) = 0.25 mol O

get the smallest number and get the ratio
For N: (0.5 mol/0.25 mol) = 2
For O: (0.25 mol/ 0.25 mol) = 1

So the empirical formula will be N2O