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A father is 4 time as old as his son.In 20 years,the father will be twice as old as his son.find the present age of each

Sagot :

Kawaiiririidn
the son is 10 yrs old and the father is 40 yrs old..

solution

let m = age of the son

4m = 20 +2m
4m- 2m =20
2m = 20 gcf 2.. divide both by 2
m= 20

therefore the son is 10 yrs old


Bellalesseidn
A father is 4 time as old as his son. In 20 years, the father will be twice as old as his son. Find the present age of each.

R: Let x = Son's age
    4x = Father's age
  
                         Present                     In 20 years
Son                        x                           x + 20
Father                    4x                          4x + 20

E: 4x + 20 = 2(x + 20)

S: 4x + 20 = 2(x + 20)
    4x + 20 = 2x + 40
    4x - 2x = 40 - 20
    [tex] \frac{2x}{2} = \frac{20}{2} [/tex]
    x = 10; 4x = 40

A: The son is 10 years old while his father is 40 years old.

C: 4x + 20 = 2(x + 20)
    4(10) + 20 = 2(x + 20)
    40 + 20 = 2(10 + 20)
    60 = 60 (Equal meaning correct)

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