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arrange all the digits from 1 to 9 only once, so that they will add to 100

Sagot :

Taskmastersidn
First of all, you clearly can't use numbers with three digits or more, because even one such number is already too much. So every number in the sum has to be either a one-digit number or a two-digit number so,if you take a digit used on the tens place, and you move it to the tens place of a different number, then that doesn't change anything.
For example,
12+3+4+57+6+8+9=99
2+13+4+57+6+8+9=99
2+13+4+7+6+58+9=99
52+3+4+17+6+8+9=99
etc. ....
The only question we have to answer is: Which digits go in the tens place, and which digits go in the ones place?


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