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Half of the size of a long bond paper would be 8.5 inches by 7 inches if halved crosswise. If halved lengthwise, the size would be 4.25 inches by 14 inches. A long bond paper originally measures 8.5 inches in width and 14 inches in height.
Size is the comparison or the measurement of length or mass. Generally, the size is the scope or dimension of something. In other words, size is how big one thing is. It is relative to the units of measurement like:
Area, on the other hand, is the measurement of a flat surface. Areas are measured usually on pieces of land or paper. In mathematics, it is used on geometrical figures. The area is noted in units squared.
In the problem, you can just logically half the paper and determine the measurements. For a better explanation, you must half the size using the area of the long bond paper.
The long bond paper’s size is 8.5 inches by 14 inches. The formula for the area of a rectangle (the shape of the long bond paper) is width multiplied by length.
1. Get the area.
A = W x L
A = 14 in x 8.5 in
A = 119 in²
2. Divide the area by 2, to get the half.
[tex]\frac{1}{2}[/tex]A = 119 in² ÷ 2
[tex]\frac{1}{2}[/tex]A = 59.5 in²
3. Use the halved area to get the new sizes and the formula for the area.
To get the crosswise size, we must keep the width of the long bond paper.
A = W x L
59.5 in² = 8.5 in x L
L = 59.5 in² ÷ 8.5 in
L = 7 in
Thus, the crosswise size of 8.5 inches by 7 inches.
To get the lengthwise size, we must keep the height of the long bond paper.
A = W x L
59.5 in² = W x 14 in
W = 59.5 in² ÷ 14 in
W = 4.25 in
Hence, the lengthwise size of 4.25 inches by 14 inches.
Here is how to get the area of a rectangle with a missing variable: https://brainly.ph/question/5505093
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