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Answer:
66795
Step-by-step explanation:
We can consider the series as an A.P (arithmetic progression) with a common difference(d) = 1 , first term (a) = 1 and last term = 365.
So the sum of n terms of the A.P is given by
S(n) = n/2( 2a + (n-1)d ).
or if we are provided with the first term and the last term then we can easily get the sum by
S(n) = n/2( a + L ) “ L = last term “
So putting the values
S = 365/2 ( 1 + 365)
= 365/2 (366)
=66795
Ans : 66795