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A bag contains 4 blue balls, 7 yellows balls and 4 white balls. Event A is defined drawing a blue ball on the first draw and event B is defined as a white ball on the second draw.

If two balls are drawn from the bag, one after another and not replaced, what is P(B|A) expressed in simplest form?

A) 2/7
B) 3/14 (which was incorrect)
C) 4/15
D) 4/11

Please help me and explain why it is the answer, thank you!

A Bag Contains 4 Blue Balls 7 Yellows Balls And 4 White Balls Event A Is Defined Drawing A Blue Ball On The First Draw And Event B Is Defined As A White Ball On class=

Sagot :

Answer:

4/14 or 29%

Step-by-step explanation:

So p(B|A) basically means that we are finding the probability of b now that a has already happened.

In this scenario once a has happened, there are 3 blue balls, 7 yellow, and 4 white so the probability is 4/14 which is approximately 29%

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