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Used 3.14 for π. Find the circumference of the following. Use C = 2 πr or C = πd
16. r = 5.5 cm C= _
17. d = 12 cm C= _
18. r = 12 cm C= _
19. d = 15 cm C= _
20. r = 5 m C= _

Read, analyse then solve.
21-25. The diameter of a bicycle wheel is 40 cm. How many complete rotations does it make over a distance of 0.5 km?
______​

Sagot :

Answer:

Direction:

Used 3.14 for π. Find the circumference of the following. Use C = 2πr or C = πd

Answer:

16.) r = 5.5 cm C = [tex]{\boxed{\tt\green{34.54\:cm}}}[/tex]

  • [tex]\tt{{2\:(\:3.14\:)(\:5.5\:cm\:)}}[/tex]
  • [tex]\tt{{2\:(\:17.27\:cm\:)}}[/tex]
  • [tex]{\boxed{\tt{Circumference\:=\:34.54\:cm}}}[/tex]

Hence, the answer is 34.54 cm

17.) d = 12 cm C = [tex]{\boxed{\tt\green{37.68\:cm}}}[/tex]

  • [tex]\tt{{(\:3.14\:)(\:12\:cm\:)}}[/tex]
  • [tex]{\boxed{\tt{Circumference\:=\:37.68\:cm}}}[/tex]

Hence, the answer is 37.68 cm.

18.) r = 12 cm C = [tex]{\boxed{\tt\green{75.36\:cm}}}[/tex]

  • [tex]\tt{{2\:(\:3.14\:)(\:12\:cm\:)}}[/tex]
  • [tex]\tt{{2\:(\:37.68\:cm\:)}}[/tex]
  • [tex]{\boxed{\tt{Circumference\:=\:75.36\:cm}}}[/tex]

Hence, the answer is 75.36 cm.

19.) d = 15 cm C = [tex]{\boxed{\tt\green{47.1\:cm}}}[/tex]

  • [tex]\tt{{(\:3.14\:)(\:15\:cm\:)}}[/tex]
  • [tex]{\boxed{\tt{Circumference\:=\:47.1\:cm}}}[/tex]

Hence, the answer is 47.1 cm.

20.) r = 5 m C = [tex]{\boxed{\tt\green{31.4\:m}}}[/tex]

  • [tex]\tt{{2\:(\:3.14\:)(\:5\:m\:)}}[/tex]
  • [tex]\tt{{2\:(\:15.7\:m\:)}}[/tex]
  • [tex]{\boxed{\tt{Circumference\:=\:31.4\:m}}}[/tex]

Hence, the answer is 31.4 m.

Direction:

Read, analyse then solve.

Solution:

21-25. The diameter of a bicycle wheel is 40 cm. How many complete rotations does it make over a distance of 0.5 km?

  • [tex]\tt{{(\:3.14\:)(\:40\:cm\:)(\:0.5\:km\:)}}[/tex]
  • [tex]\tt{{(\:3.14\:)(\:20\:cm\:)}}[/tex]
  • [tex]{\boxed{\tt{62.8\:cm}}}[/tex]

Hence, the answer is 62.8 cm.

Answer:

  • The number of complete rotations does it make over a distance of 0.5 km is [tex]{\boxed{\tt\green{62.8\:cm}}}[/tex]

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