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15te-12he+10ty-8hy by using factoring polynomial

Sagot :

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ANSWER:

(5t - 4h ) (3e + 2y)

EXPLANATION:

15te-12he+10ty-8hy

Group the first two terms together and the last two terms together.

(15te-12he)(10ty-8hy)

Apply common monomial factoring, which is to find the GCF (Greatest Common Factor), GCF is the first factor, and dividing each term by the GCF to get the other factor.

In (15te-12he), the GCF is 3e, then divide each term (15te-12he) by 3e

This will result to 3e (5t - 4h)

In (10ty-8hy), the GCF is 2y, then divide each term (10ty-8hy) by 2y

This will result to 2y (5t - 4h)

3e (5t - 4h) 2y (5t - 4h )

Then apply common monomial factoring again, and the GCF is (5t - 4h ) , so factor out (5t - 4h ) from the expression

(5t - 4h ) (3e + 2y)

SOLUTION (only):

15te-12he+10ty-8hy

=(15te-12he)(10ty-8hy)

=3e (5t - 4h)2y (5t - 4h)

=(5t - 4h ) (3e + 2y)

CHECKING:

(5t - 4h ) (3e + 2y)

Calculate the product using FOIL ( First, Out, In and Last) method

Multiply each term in the 1st parentheses by each term in the 2nd parentheses

=5t × 3e + 5t × 2y - 4h × 3e  - 4h × 2y

Calculate the product

= 15 te + 10 ty - 12 he - 8 hy

or

=15te-12he+10ty-8hy

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