ACTIVITY 2: LET'S COMPUTE AND CHECK IT RIGHT!
DIRECTIONS: READ THE GIVEN PROBLEM. FILL IN THE TABLE WITH CORRECT DATA,THEN SOLVED AND CHECK IT USING BOYLE'S LAW EQUATION: P¹V¹=P²V². PROBLEM TO BE SOLVED AND TO BE CHECKED USING BOYLE'S LAW EQUATION:
In a J-shaped tube filled with mercury,initially, mercury levels in both limbs are the same.The initial volume of the trapped gas in the closed end is 0.50 L.The volume of the gas decreases to 0.30 L after the addition of mercury from the open end of the tube. Take note that the opened end of the tube is subjected to the atmosphere; thus,the initial pressure is equal to atmospheric pressure ( 1 atm = 760 mmHg). what will be the final pressure after the changes of volume happened?
Given:
Find:
Equation:
Substitution:
Solution:
Final Answer:
DATA
Given:
V¹=_____L
V²=_____L
P¹=_____ mmHg
Find:
Final Pressure
Equation:
P²=P¹V¹/V²
Substitution:
Solution:
Final Answer:
CHECKED BY V²
Given:
Find:
Final Volume
Equation:
V²=P¹V¹/P²
Substitution:
Solution:
Final Answer:
CHECKED BY P¹
Given:
Find:
Initial Volume
Equation:
P¹=P²V²/V¹
Substitution:
Solution:
Final Answer:
Closure: The computations you made in this activity explain that gases spread in the medium, and at constant temperature, the volume of a gas decreased if the pressure is increased, and vice versa.