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A flagpole casts a shadow that is 15 feet long.the angle of elevation at this is 50.How tall is the flagpole

Sagot :

[tex]\bold {PROBLEM:}[/tex]

A flagpole casts a shadow that is 15 feet long.the angle of elevation at this is 50. How tall is the flagpole?

[tex]\bold {GIVEN:}[/tex]

  • distance (adjacent) = 15 ft.
  • angle of elevation = 50°

[tex]\bold {SOLVE\:FOR:}[/tex]

  • height (opposite)

[tex]\bold {SOLUTION:}[/tex]

The function is tangent

[tex] \begin{array}{c} \large \tt tan \theta = \frac{opposite}{adjacent} \\ \\ \large \tt tan50 = \frac{h}{15} \\ \\ \large \tt (15)(tan50) = ( \frac{h}{ \cancel{15}} )( \cancel{15}) \\ \\ \large \tt (15)(tan50) = h\\ \\ \large \tt h = (15)(tan50) \\ \\ \large\red{\boxed{ \tt h = 17.876}}\end{array}[/tex]

[tex]\\[/tex]

[tex]\therefore\boxed{\textsf{The flagpole is 17.876 feet tall.}}[/tex]

[tex]\\ \\[/tex]

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