Emssnylammeidn
Answered

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Eugenol (C10H12O2) is known to be found in nutmeg, cinnamon, basil and

nutmeg. What is the boiling point of a solution containing 0.144 g of this

compound dissolved in 10.0 g of benzene? (Kb= 2.53 °C/m), Bpt(benzene)=

80.10 °C and Molar mass of C10H12O2= 164.2 g/mol ​

Sagot :

Given:

mass of solute = 0.144 g

mass of solvent = 10.0 g = 0.0100 kg

molar mass of solute = 164.2 g/mol

[tex]\text{BP}_{solvent} = \text{80.10°C}[/tex]

[tex]K_{\text{b}} = \text{2.53°C/molal}[/tex]

solute: eugenol

solvent: benzene

Required:

[tex]\text{BP}_{solution}[/tex]

Solution:

Step 1: Calculate the number of moles of solute.

[tex]\text{moles of solute} = \frac{\text{mass of solute}}{\text{molar mass of solute}}[/tex]

[tex]\text{moles of solute} = \frac{\text{0.144 g}}{\text{164.2 g/mol}}[/tex]

[tex]\text{moles of solute} = 8.76979 × 10^{-4} \: \text{mol}[/tex]

Step 2: Calculate the molality of solution.

[tex]m = \frac{\text{moles of solute}}{\text{mass of solvent}}[/tex]

[tex]m = \frac{8.76979 × 10^{-4} \: \text{mol}}{\text{0.0100 kg}}[/tex]

[tex]m = \text{0.0876979 molal}[/tex]

Step 3: Calculate the boiling point elevation.

[tex]\Delta T_{\text{b}} = mK_{\text{b}}[/tex]

[tex]\Delta T_{\text{b}} = (\text{0.0876979 molal})(\text{2.53°C/molal})[/tex]

[tex]\Delta T_{\text{b}} = \text{0.222°C}[/tex]

Step 4: Calculate the boiling point of the solution.

[tex]\text{BP}_{solution} = \text{BP}_{solvent} + \Delta T_{\text{b}}[/tex]

[tex]\text{BP}_{solution} = \text{80.10°C} + \text{0.222°C}[/tex]

[tex]\boxed{\text{BP}_{solution} = \text{80.322°C}}[/tex]

[tex]\\[/tex]

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