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A 450mL balloon is filled with helium at 750 mmHg barometric pressure. The balloon is released and climbs to an altitude where the barometric pressure is 30 mmHg. What will the volume of the balloon be if during the ascent, the temperature drops from 20 to 5 degrees Celsius (Combined Gas Law)

Sagot :

Given:

[tex]P_{1} = \text{750 mmHg}[/tex]

[tex]T_{1} = \text{20°C + 273 = 293 K}[/tex]

[tex]V_{1} = \text{450 mL}[/tex]

[tex]P_{2} = \text{30 mmHg}[/tex]

[tex]T_{2} = \text{5°C + 273 = 278 K}[/tex]

Unknown:

[tex]V_{2}[/tex]

Solution:

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

[tex]V_{2} = V_{1} × \frac{P_{1}}{P_{2}} × \frac{T_{2}}{T_{1}}[/tex]

[tex]V_{2} = \text{450 mL} × \frac{\text{750 mmHg}}{\text{30 mm Hg}} × \frac{\text{278 K}}{\text{293 K}}[/tex]

[tex]\boxed{V_{2} = \text{10674 mL}}[/tex]

[tex]\\[/tex]

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