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Sagot :
Always remember this relationship: Speed = Distance/ Time.
For Hubert: Speed = 10kph, time = 10 mins, Distance = unknown.
For Banjo: Speed = 8kph, time = 10 mins, Distance = unknown.
Lets D1 = distance traveled by Hubert in 10mins
D2 =distance traveled by Banjo in 10mins
Then solve for individual distances traveled using the relationship above:
For Hubert: D1 = Speed x Time
D1 = (10km/hr)(10min)(1hr/60min)
D1 = 100/60 km
D1 = 1.67 km
For Banjo: D2 = Speed x Time
D2 = (8km/hr)(10min)(1hr/60min)
D2 = 80/60 km
D2 = 1.33 km
Since they traveled in opposite direction after 10 mins, just add their individual distances//then Dtotal = 1.67 + 1.33 = 3 km..
For Hubert: Speed = 10kph, time = 10 mins, Distance = unknown.
For Banjo: Speed = 8kph, time = 10 mins, Distance = unknown.
Lets D1 = distance traveled by Hubert in 10mins
D2 =distance traveled by Banjo in 10mins
Then solve for individual distances traveled using the relationship above:
For Hubert: D1 = Speed x Time
D1 = (10km/hr)(10min)(1hr/60min)
D1 = 100/60 km
D1 = 1.67 km
For Banjo: D2 = Speed x Time
D2 = (8km/hr)(10min)(1hr/60min)
D2 = 80/60 km
D2 = 1.33 km
Since they traveled in opposite direction after 10 mins, just add their individual distances//then Dtotal = 1.67 + 1.33 = 3 km..
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