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If a varies inversely as b, and a = ⅓ when b = 12, find a when b = -8.​

If A Varies Inversely As B And A When B 12 Find A When B 8 class=

Sagot :

Inverse Variation

If a varies inversely as b, and a = ⅓ when b = 12, find a when b = -8.

[tex]\:[/tex]

Equation of variation: [tex]\tt \Large \blue{\bold{a = \frac{k}{b}}}[/tex]

Constant of variation: [tex]\tt \Large \green{\bold{k = ab}}[/tex]

[tex]\:[/tex]

Solve for k.

[tex]\tt \Large \rightarrow \green{\bold{k = ab}}[/tex]

[tex]\tt \Large \rightarrow k = \frac{1}{3} \times 12[/tex]

[tex]\tt \Large \rightarrow k = \frac{1 \times 12}{3}[/tex]

[tex]\tt \Large \rightarrow k = \frac{12}{3}[/tex]

[tex]\tt \Large \rightarrow \green{\bold{k = 4}}[/tex]

[tex]\:[/tex]

Find a when b = -8.

[tex]\tt \Large \rightarrow \blue{\bold{a = \frac{k}{b}}}[/tex]

[tex]\tt \Large \rightarrow a = \frac{4}{-8}[/tex]

[tex]\tt \Large \rightarrow a = -\frac{4}{8}[/tex]

[tex]\tt \Large \rightarrow \purple{\bold{a = -\frac{1}{2}}}[/tex]

[tex]\:[/tex]

Answer:

b. [tex]\tt \Large \purple{\bold{-\frac{1}{2}}}[/tex]

[tex]\:[/tex]

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