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EXERCISE 1
MNOP is a trapezoid with PO as the longer base and MN as the shorter base. The midpoint of NO is R while that of PM is Q.
1. Let the m∠M = 110°. Find m∠N
2. Let PM= ON and m∠N = 125°. Find m∠P.
3. Let PM= ON and OR= 8 inches. Find PM.
4. Let PO= 40 cm and MN= 28 cm. Find QR.
5. Let MN= 34 ft. and QR= 47 ft. Find PO.
6. Let PM=ON and the perimeter of MNOP=68 m. The shorter base is X meters. The longer base is twice the length of the smaller base. Each leg is 4 m longer than the smaller base. Find the length of each side.

Note: Nonsense answer will be REPORTED

EXERCISE 1 MNOP Is A Trapezoid With PO As The Longer Base And MN As The Shorter Base The Midpoint Of NO Is R While That Of PM Is Q 1 Let The MM 110 Find MN 2 Le class=

Sagot :

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Answer:

1. 110°

2. 55°

3. 16in

4. 34cn

5. 60ft

6. MN = 12m

PM = ON = 12 + 4 = 16m

PO = 2(12) = 24m

Step-by-step explanation:

  • MNOP is an isosceles trapezoid
  • it has two equal base angles
  • two legs are equal
  • two parallel bases

1. m∠M = m∠N

2.

sum of the interior angles of isosceles trapezoid = 360

m∠M + m∠N + m∠O + m∠P = 360

m∠M = m∠N = 125° AND m∠O = m∠P = x

125 + 125 + X + X = 360

x = 55

3.OR = ½ PM

4. Median of isosceles trapezoid = ½(sum of two bases)

QR = ½( MN + PO)

= ½(40 + 28)

= 34

5. QR = ½( MN + PO)

47 = ½( 34 + PO )

94 = 34 + PO

PO = 60

6. P = MN + PO + MP + NO

MN = x

MP = NO = x +4

PO = 2x

P = 60

60 = x + x +4 + x +4 + 2x

x = 12 = MN

MP = NO = 12+4 = 16

PO = 2(12) = 24

(SANA NAKATULONG)

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