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GAY LUSSAC'S LAW (SHOW YOUR SOLUTION)
A sample of gas exerted a pressure of 745 mmHg at 30°C. What would be the temperature required to change the pressure to standard conditions?

Sagot :

Given:

[tex]P_{1} = \text{745 mmHg}[/tex]

[tex]T_{1} = \text{30°C + 273 = 303 K}[/tex]

[tex]P_{2} = \text{760 mmHg}[/tex]

Required:

[tex]T_{2}[/tex]

Solution:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

[tex]T_{2} = T_{1} × \frac{P_{2}}{P_{1}}[/tex]

[tex]T_{2} = \text{303 K} × \frac{\text{760 mmHg}}{\text{745 mmHg}}[/tex]

[tex]\boxed{T_{2} = \text{309 K}}[/tex]

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