Goldaiken326idn
Answered

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The average loan of an employee is Php18,200. If the debt is normally distributed with

a standard deviation of Php6,150, find the probabilities;

a. that the employee owes more than Php20,000. (5points)

b. that the employee owes between Php10,000 and Php25,000. (5points)​

Sagot :

Jedsanpangetidn

Answer:

The average loan of an employee is Php18,200. If the debt is normally distributed with a standard deviation of Php6,150, find the probabilities;

a. that the employee owes more than Php20,000.

z= 20,000-18,200/6,150

=1.8/6,150

=0.29

=0.6141

b. that the employee owes between Php10,000 and Php25,000.

z= 10,000-18,200/6,150 z= 25,000-18,200/6,150

= -8.2/6,150 =6.8/6,150

= -1.33 =0.65

z =0.0918 z=0.7422

0.0918-0.7422= -0.6504

YAN PO I

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