Factor m^2 – 5mn – 14n^2.

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29-05-2015
Math

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Factor m^2 – 5mn – 14n^2.

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Mlcparra16idn Mlcparra16idn · Answer 1 · 2015-05-29T20:54:10+08:00

Mlcparra16idn Mlcparra16idn

29-05-2015

We treat this as a quadratic equation for m. So we need to look for two terms with a product of -14n² and a sum of -5n. We will find out that the two terms are -7n and 2n
So:
[tex]m^2-5mn-14n^2=(m-7n)(m+2n)[/tex]

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Factor m^2 – 5mn – 14n^2.

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