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Find the area of a trapezoid with an altitude of 3.36 cm, with bases of 7.25 cm and 9.64 cm.

Sagot :

The formula for the area of a trapezoid is:
[tex]A=\frac{1}{2}h(b_1+b_2)[/tex]

Substitute the given measurements
[tex]A=\frac{1}{2}(3.36 cm)(7.25 cm+9.64 cm)[/tex]
[tex]A=(1.68 cm)(16.89 cm)[/tex]
A=28.3752 cm²

Hope this helps =)
finding the area of trapezoid:

[tex]A = \frac{( b_{1} + b_{2} ) . h} {2} [/tex]

[tex]b_{1} = 7.25 cm, b_{2} = 9.64 cm, h = 3.36 cm[/tex]

[tex]A = \frac{( 7.25 + 9.64) 3.36 } {2} [/tex]

[tex]A = \frac{ 56.7504 cm } {2}[/tex]

A = 28. 3752 cm²