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What is the equation of the straight line of the:" (-1,6) and (2,1)?

Sagot :

Find the slope first:
[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\frac{6-1}{-1-2}[/tex]
[tex]\frac{5}{-3}[/tex]

Now substitute to the formula
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-1=\frac{5}{-3}(x-2)[/tex]
Multiply both sides by -3
-3y+3=5x-10
Subtract both sides by 3
-3y=5x-13
Divide both sides by -1
3y=-5x+13

Hope this helps =)