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Jose paid at most Php 250 for the 4 markers and 3 pencils that he bought. Suppose
the marker is more expensive than the pencil and their price’s difference is greater
than Php 30. Which of the following could be the amount paid by Jose for each
item?
a. Marker: Php 56 c. Marker: Php 46
Pencil: Php 12 Pencil: Php 7
b. Marker: Php 35 d. Marker: Php 50
Pencil: Php 15 Pencil: Php 19

Sagot :

Lets represent:
x=price per marker
y=price per pencil

4x+3y=250

x=y+30

Substitute
4(y+30)+3y=250
4y+120+3y=250
7y+120=250
Subtract both sides by 120
7y=130
y=18.57 or simply 19

Substitute the value of y to x\
x=y+30
x=19+30
x=49
Or in the choices, 50

So the answer is D

Hope this helps =)