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a woman owns 21 pets. each of her pets is either a cat or bird. if the pets have a total of 76 legs, and assuming that none of the bird's legs are protruding form any of the cats' jaws, how many cats and how many birds does the woman own?

Sagot :

Mlcparra16idn
Okay so if you want to learn more about questions like this search for head and feet math problems.

We know that the woman has 21 pets which are either a cat or a bird and the total number of legs is 76.

We know that a cat has 4 legs and a bird has 2 feet

So we assume that all pets are cats
If this is so the total number of legs would be 4*21=84

The difference between the number of feet the bird and cat has is 2

In order to get the number of gets the expression would be:
[tex] \frac{84-76}{4-2} = \frac{8}{2} =4[/tex]

Therefore there are 4 birds and 21-4=17 cats.
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