Answered

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A boy is 10 yrs older than his brother. In 4 yrs he will be
twice as age as his brother. Find the present age of each.

Sagot :

Shinalcantaraidn

let 'x' be the age of the boy at present

'y' be the age of his brother at present

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the boy is 10 years older than his brother

x = 10 + y     ----------equation 1

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in 4 years, he will be twice as his brother's age

in 4 years, 'x+4' is the boy's age

                 'y+4' is his brother's age

x + 4 = 2(y+4)    -------equation 2

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substitute equation 1 to equation 2

10 + y + 4 = 2(y+4)

10 + y + 4 = 2y + 8

10+4-8 = 2y-y

6 = y

y = 6

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Substitute y = 6 to equation 1

x = 10 + y

x = 10 + 6

x = 16

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Therefore the age of the boy is 16 and his brother's age is 6

JohnMorE145idn
A boy is ten and his brother will be twice his age in 4 years so it means that in 4 years his brother will be 6 and a boy will be 16.
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