Given:
C(-1,7)
P(1,2)
given that P is the other end of diameter and C is the center we can say that C is the mid point of the diameter. to find the other end we use the mid point of a line segment formula:
[tex] x_{m} = \frac{ x_{1}+ x_{2} }{2} [/tex]
and
[tex] y_{m} = \frac{ y_{1}+ y_{2} }{2} [/tex]
Solution:
[tex] -1 = \frac{1+ x_{2} }{2} [/tex]
[tex] x_{2} = -3[/tex]
[tex] 7 = \frac{2+ y_{2} }{2} [/tex]
[tex] y_{2} = 12[/tex]
therefor, the other end of diameter or [tex] P_{2} [/tex]
[tex] P_{2}(-3,12) [/tex]
