Makakuha ng mga maaasahang sagot sa iyong mga tanong sa IDNStudy.com. Ang aming komunidad ay handang magbigay ng malalim at maaasahang mga sagot, anuman ang kahirapan ng iyong mga katanungan.

one of the diagonals of a rhombus is twice as the other.if the sum of the lengths of the diagonals is 24, find the area of the rhombus

Sagot :

The first diagonal-x
The second diagonal-y

y=2x
because it says one diagonal is twice the other
x+y=24
The sum of the length of the diagonals is 24. Therefore substitute the value of y.
x+2x=24
Add like terms
3x=24
Divide both sides by 3
x=8

Therefore the first diagonal is 8 and the second is 16. Now the formula for the area of the rhombus given its diagonals is:
[tex]A=\frac{pq}{2}[/tex]
Substitute the diagonals
[tex]A=\frac{(8)(16)}{2}[/tex]
[tex]A=\frac{128}{2}[/tex]
A=64 sqr. units

The area is 64 sqr. units. Hope this helps =)