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A motorcycle driver travels 15kph faster than a bicycle rider. the motorcycle driver cover 60km in two hours less than time it takes the bicycle driver to travel the same distance.

Sagot :

let [tex] V_{b}[/tex] be velocity of bicycle
let [tex] t_{b}[/tex] be time traveled of bicycle

Given:
[tex] V_{m} = V_{b}+15 kph [/tex]
[tex] t_{m} = t_{b} -2 hrs[/tex]
[tex] d_{b} = d_{m} = 60 km[/tex]

formula:

[tex]d=Velocity[/tex] [tex]x[/tex] [tex]time[/tex]

[tex]time= \frac{distance}{Velocity} [/tex]

Solution:
time for bicycle

[tex] t_{b}= \frac{60}{ V_{b} } [/tex]

use [tex] t_{b} [/tex] on [tex] d_{m} = V_{m} [/tex] [tex]x[/tex] [tex] t_{m} [/tex]

[tex]60km=( V_{b}+15)( \frac{60}{ V_{b} }-2) [/tex]

[tex] V_{b} =15kph[/tex]

use [tex] V_{b} =15kph[/tex] on [tex] t_{b}= \frac{60}{ V_{b} } [/tex]

[tex] t_{b}= \frac{60}{15kph} [/tex]

[tex] t_{b} = 4 hrs[/tex]

solve for [tex] t_{m} [/tex]:

[tex] t_{m} = 4hrs -2 hrs[/tex]

[tex] t_{m} =2hrs[/tex]

solve for [tex] V_{m} [/tex]:

[tex] V_{m} = 15kph+15 kph [/tex]

[tex] V_{m} =30kph[/tex]