CIRCLE
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Solve:
A full orbit or a full angle of a circle 360° in a measure of each number, find the value of x as the given.
[tex] \implies\sf x° + 3x° + 3x° + 4x° + 5x° = 360°[/tex]
[tex] \implies \sf \large 16x° = 360°[/tex]
[tex] \implies\sf \large \frac{ \cancel{16}x°}{ \cancel{16} \degree} = \frac{360 \degree}{ 16 \degree} \\ [/tex]
[tex] \implies \sf \large \therefore \: x = 22.5[/tex]
[tex] \: [/tex]
Now substitute x as 22.5 to find each measure and check.
[tex] \large \begin{cases} \begin{align} \sf \: 22.5 \degree \\ \sf \: (3)22.5 \degree \\ \sf \: (3)22.5 \degree \\ \sf \: (4)22.5 \degree\\ \sf \: (5)22.5 \degree \end{align} \end{cases} \: \: \begin{align} = \\ = \\ = \\ = \\ = \end{align} \: \: \begin{align} \sf \: \orange{22.5 \degree}\\ \sf \: \orange{67.5 \degree} \\ \sf \: \orange{67.5 \degree} \\ \sf \: \orange{90.0 \degree} \\ \sf \: \orange{112.5 \degree} \end{align}[/tex]
[tex] \: [/tex]
Final Answer:
[tex] \large\sf \underline{ \underline{\orange{22.5°,67.5°,67.5°,90° \: and \: 112.5°}}}[/tex]
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#CarryOnLearning
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