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The area of the rectangle is 1260 square centimeters. Find the dimensions of the rectangle if its length is 12 cm greater than its width.

1. What is the value of the length?
2. What is the representation for the length
3. What is the representation for the width?
4. What is the equation?
5. What are the values of x?
6. What is the value of the width?



Sagot :

Answer:

1. 42

2. length = x + 12

3. width = x

4. x(x+12) = 1260

5. 30 and -42

6. x = 30, discard -42 since it is not a whole number

Step-by-step explanation:

[tex]x(x + 12) = 1260 \\ {x}^{2} + 12x - 1260 = 0 \\ (x - 30)(x + 42) = 0 \\ x - 30 = 0 \\ x + 42 = 0 \\ \\ x = 30 \\ x = - 42[/tex]