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1. Which is equivalent to (5xºy-²)-¹

Sagot :

Answer:

[tex]\frac{y^2}{5}[/tex]

Step-by-step explanation:

[tex](5x^0y^{-2})^{-1}[/tex]

All quantity raised to zero is equal to 1. Therefore x⁰ = 1

[tex](5(1)y^{-2})^{-1}[/tex]

Apply the rule [tex]a^{-b} = \frac{1}{a^b}[/tex] to solve [tex]y^{-2}[/tex]

[tex](5)(\frac{1}{y^2} )^{-1}[/tex]

[tex](\frac{5}{y^2} )^{-1}[/tex]

Apply the rule [tex]a^{-b} = \frac{1}{a^b}[/tex] again

[tex](\frac{5}{y^2} )^{-1} = \frac{1}{(\frac{5}{y^2})^1 }[/tex]

[tex](\frac{5}{y^2} )^{-1} = \frac{y^2}{5}[/tex]

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