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7.P (X < 15 given m-15 and s-3)=P(Z < (15-15)/3=0)=0.5 1.67)=1-P(Zs1.67)=1-0.9525=0.0475 (b) P (X> 20 given m=15 and s=3) (c) P (10 ≤X ≤ 20 given m=15 and = P(Z > (20-15)/3 = s-3)=P((10-15)/3 ≤ Z≤ (20-15)/3)=P(-1.67 Z≤ 1.67) = 1(1.67)-1(-1.67)=0.9525-0.0475 = 0.905 7. Suppose scores on an IQ test are normally distributed. If the test has a mean of 100 and a standard deviation of 10, what is the probability that a person who takes the test will score between 90 and 110?