Answer:
Claculate the density, specific weight and specific volume of chlorine gas at 25°C and under a pressure of 600 KPa absolute.The gas constant R for chlorine is 117 N-m/Kg-k.
\bold{Solution:}Solution:
1. Use this equation to get the density
p = \frac{p}{RT}p=
RT
p
p = \frac{600}{(117) \: (25 + 273)}p=
(117)(25+273)
600
p = 17.2 \: Kg /{m}^{3}p=17.2Kg/m
3
2. Equation Gives the Specific Weight
w = pgw=pg
w = 17.2 \: \times \: 9.81 \: = 168.732N/ {m}^{3}w=17.2×9.81=168.732N/m
3
3. The Specific Volume
v = \frac{1}{p}v=
p
1
v = \frac{1}{17.2}v=
17.2
1
v = 0.058 {m}^{3}/Kgv=0.058m
3
/Kg
Step-by-step explanation:
hope it helps po
