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Sagot :

[tex] \mathbb{ \underline{PROBLEM:}}[/tex]

3. The area of this trapezoid is [tex] \large \tt25.5 ft {}^{2} [/tex].

What is the height of the trapezoid? Show your work.

[tex] \mathbb{ \underline{SOLUTION:}}[/tex]

Area of a trapezoid = [tex] \tt \frac{1}{2} (a + b)h[/tex]

where a and b are the bases and h is the heigth

Given;

  • Area = [tex] \tt25.5 \: ft {}^{2} [/tex]

  • Base a = [tex] \tt3.2 \: ft[/tex]

  • Base b = [tex] \tt7 \: ft[/tex]

[tex]\begin{gathered}\begin{gathered}\begin{array}{|c|}\hline \tt 25 .5 = \frac{1}{2} (3.2 + 7)h \\ \\ \tt25.5 = 5.1 \: h \\ \\ \tt h = \red{5} \\ \hline \end{array}\end{gathered}\end{gathered}[/tex]

[tex] \mathbb{ \underline{ANSWER:}}[/tex]

Thus, the height of the trapezoid is 5 .

[tex] \\ [/tex]

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