Answer:
1.[tex]=4\left(x^3+2x^2y^2+3y^3\right)[/tex]
2.[tex]=20x^6+5x^3[/tex]
3.[tex]=+\cdot \:p\cdot \left(p^2q+pq^2r^2\right)\cdot \:q\cdot \:r^2[/tex]
Step-by-step explanation:
1. Rewrite 12 as [tex]3\cdot \:4[/tex]
Rewrite 8 as [tex]2\cdot \:4[/tex]
[tex]=4x^3+2\cdot \:4x^2y^2+3\cdot \:4y^3[/tex]
Factor out common term 4
[tex]=4\left(x^3+2x^2y^2+3y^3\right)[/tex]
2. Apply rule [tex]a^{1}=a[/tex]
[tex]x^{1} =x[/tex]
[tex]=5x^3+20x^6+35\cdot \:0\cdot \:x[/tex]
Apply rule [tex]0\cdot \:a=0[/tex]
[tex]=5x^3+20x^6+0[/tex]
[tex]5x^3+20x^6+0=5x^3+20x^6[/tex]
[tex]=20x^6+5x^3[/tex]
3.Find Least Common Multiplier of [tex]p^2q\:+\:pq^2r^2\:-\:pqr\:+\:pqr^2[/tex]
Lowest Common Multiplier (LCM)
The LCM of a, b is the smallest multiplier that is duvisible by both a and b
Factor [tex]+pqr^2[/tex]
[tex]p^2q\:+\:pq^2r^2\:-\:pqr\:+\:pqr^2[/tex]
Multiply each factor with the highest power:
[tex]p^2q\:+\:pq^2r^2\:-\:pqr\:+\:pqr^2[/tex]
I hope this is helpful :)
SAITAMA!!
